WebJun 14, 2014 · import datetime data1 = datetime.datetime.now () data2 = datetime.datetime.now () diff = data2 - data1 days, seconds = diff.days, diff.seconds hours = days * 24 + seconds // 3600 minutes = (seconds % 3600) // 60 seconds = seconds % 60 print hours,minutes,seconds Share Improve this answer Follow edited Jul 27, 2024 at … WebMay 26, 2024 · 1 -- Create two dates Let's create two dates objects in python using the module datetime: import datetime year = 2008 month = 7 day = 8 hour = 12 minute = 47 …
Python program to find number of days between two given dates
WebFeb 27, 2024 · from datetime import datetime date1 = datetime.now () date2 = datetime (day= 1, month= 7, year= 2024 ) timedelta = date2 - date1 print (timedelta) This returns a timedelta object, which contains days, seconds and microseconds and represents the duration between any two date / time or datetime objects. WebMay 21, 2015 · I'm trying to find the date difference between two date columns using the below code. But, I'm not getting the expected result. I'm a beginner. e.g. Start Date is 2016-02-18 00:00:00 and End Date is 2015-05-21 00:00:00, the difference between these two dates is -273, but, the actual output is 273000000 tpics 5.0
Python - Exclude weekends between two Dates - Stack Overflow
WebPython: Get difference between two datetimes in minutes datetime.date : An object of date class specifies a date using year, month and day datetime.time : An object of time … WebSelect values between particular times of the day (e.g., 9:00-9:30 AM). By setting start_time to be later than end_time , you can get the times that are not between the two times. Parameters start_timedatetime.time or str Initial time as a time filter limit. end_timedatetime.time or str End time as a time filter limit. WebSep 5, 2014 · Sorted by: 12 dateutil.parser.parse returns datetime.datetime objects which you can subtract from each other to get a datetime.timedelta object, the difference between two times. You can then use the total_seconds method to get the number of seconds. diff = date2 - date1 print (diff.total_seconds ()) tpics5.0