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If the work required to stretch a spring 1 ft

Web23 mei 2024 · Explanation: work done = force * extension. here, the extension would be actually be the change in length of the spring's extension. the final length in question is … Web23 okt. 2024 · The work required to stretch it 9 inches Given that : Work (W) = kx Take the integral of W at 3 fts beyond its natural length; W = ∫kx dx at 0 to 3 W = k ∫xdx at 0 to 3 W = 6 W = k [x²/2] at x =0 to x = 3 6 = k [3² /2] - 0 6 = k [9/2] 12 = 9k k = 12/9 = 4/3 = 1.333 Converting inches to feet: 1 inch 0.0833 ft 9 inches = 0.75 ft

If the work required to stretch a spring 1 ft beyond its natural

WebSolution for If the work required to stretch a spring 1 ft beyond its natural length is 9 ft-lb, how much work is needed to stretch it 9 in. beyond its natural… Web-Eighteen foot-pounds of work is required to stretch a spring 4 inches from its natural length. Find the work required to stretch the spring an additional 3 inches. Solutions Verified Solution A Solution B Reveal all steps Create an account to view solutions By signing up, you accept Quizlet's Terms of Service and Privacy Policy the depot mill valley https://groupe-visite.com

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Webto find the amount of work done in this situation. We could first notice that we're given when a spring is stretch two inches, that £10 of force is applied. And we could substitute … Web8 sep. 2024 · A force of 10 lb is required to hold a spring stretched 4in.beyond its natural length. How much work The Answer Key 16.3K subscribers Subscribe 2.5K views 2 years ago A force of 10 lb is... Web4 dec. 2011 · If the work required to stretch a spring 1 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in. beyond its natural length? asked by Ryan December 4, 2011 Answer this Question Your Name Your Answer Still need help? You can ask a new question or browse more Calculus questions. the depot nursling southampton

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If the work required to stretch a spring 1 ft

Answered: If the work required to stretch a… bartleby

Webfor the flying problem we're going to be considering the work required to stretch a spring one ft beyond its natural length of 12. But we know that that's only 12 ft lb. We want to … Web5 mei 2024 · Q: Suppose the work W_0 done when a spring is stretched 6 inches from its natural length is 1/2 ft-lb. Find the work W done in extending the spring 3 more inches. …

If the work required to stretch a spring 1 ft

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WebSo, the work needed to stretch a spring from 60 cm to 74 cm is. A = A 3 - A 2 = 21025/4 - 5625/4 = 3850 J. Need a fast expert's response? Submit order. and get a quick answer … WebHow much work is done in stretching the spring 1 feet beyond its natural length? A force of 10 lbs for 4 inches f = k*d Where f= force k = spring constant e = extension k = f/e = …

WebFormula Used. Spring work = Spring Constant* (Displacement at point 2^2-Displacement at point 1^2)/2. Wspring = Kspring* (x2^2-x1^2)/2. This formula uses 4 Variables. … WebIf the work required to stretch a spring 1 ft beyond its natural length is 12 ft-lb, how much work (in ft-lb) is needed to stretch it 3 in. beyond its natural length? This problem has …

Webphysics. A 20.0 g copper ring at 0.000 degree Celsius has an inner diameter of D=2.54000 cm. An aluminum sphere at 100.0 degree Celsius has a diameter of d=2.54508 \mathrm …

WebWe need to find the stiffness of the spring: x 1 = L 2 -L 1 = 47 - 31 = 16 cm; F = k*x 1 ==> k = F/x 1 = 200/16 = 25/2. Let's find the work needed to stretch a spring from 31 cm to 46 cm: x 2 = L 3 -L 1 = 46 - 31 = 15 cm A 2 = k*x 2 ²/2 = 25/2 * 15² / 2 = 5625/4 J. Let's find the work needed to stretch a spring from 31 cm to 70 cm:

WebIf the work required to stretch a spring 1 ft beyond its natural length is 1… 0:00. A force of 10 lb is required to hold a spring stretched 4 in. beyond its nat… 02:19. A force of 10 … the depot paeroaWebWork done in stretching a spring to x length is W = 2 1 k x 2 ∴ Work one in stretching from x 1 to x 2 is proportional to W ∝ x 2 2 − x 1 2 hence W 1 0, 2 0 W 2 0, 3 0 = 3 0 0 5 … the depot odessa tx menuWebAn overhead garage door has two springs, one on each side of the door. A force of 15 pounds is required to stretch each spring 1 foot. Because of the pulley system, the … the depot florala alWeb10 mrt. 2024 · A force of 4 pounds is required to hold a spring stretched 0.1 feet beyond its natural length. How much work (in foot-pounds) is done in stretching the spring from its natural length to 0.6 feet beyond its natural length? asked by maggie March 10, 2024 2 answers This should clear it up for you... the depot long beach waWebGet an answer for 'Use Hooke's Law to determine the variable force in the spring problem. An overhead garage door has two springs, one on each side of the door. A force of 15 pounds is required to ... the depot restaurant dobsonWebIf the work required to stretch a spring 1 ft beyond its natural length is 12 ft-lb, how much work is needed to stretch it 9 in. beyond its natural Do my homework now. If the work … the depot oconomowoc menuWebIf the work required to stretch a spring 1 foot beyond its natural length is 12 foot pounds, how much work is needed to stretch it 9 inches beyond its natural length? The work W done in stretching a spring from — a units beyond its natural length to a; = b units beyond its natural length is W = f (x) d:r. the depot restaurant in visalia ca