http://bbc.nvg.org/doc/Master%20512%20Technical%20Guide/m512techb_int21.htm Nettet6. aug. 2024 · Your problem is that your using INT 21h without loading the number of the MS-DOS service you want to use into the AH register. So instead of invoking the service you want to use, it invokes whatever service happens to correspond to the value that happens to be in AH. – Ross Ridge Apr 27, 2016 at 21:50 1
用8086汇编语言编写一个输入字符串的程序_软件运维_内存溢出
Nettet20. aug. 2015 · The code in my answer is valid 16-bit code. Though it might require an 80286 or 80386 to run, because of the use of EAX. The simple fix would be to change all occurrences of EAX to AX (though this would limit you to printing 16-bit values). – Michael Aug 20, 2015 at 14:58 Nettet2. okt. 2016 · You'll need to make use of routines provided by either the OS or the BIOS in order to read a character and then build on top of this. You've tagged the question with emu8086 which claims to have a DOS interface. In that case you can use int 21h with ah set to either 1 or 7 to read a character. cisco jabber transferring calls
dos - Difference between 07h and 08h services of INT 21h in 8086 ...
Nettet7. jul. 2016 · 4 Hours range from 0 to 23. Minutes from 0 to 59. They are two digits numbers and as such must be handled. There is no built-in service that prints numbers, the Int 21/AH=02h prints characters, you need to transform a two digits number (an 8 bit quantity) into a two characters (two 8 bit quantities) 1. Nettet15. feb. 2024 · 1 Im creating an 8086 assembly program to ask a user to input a decimal value, add 5 to it and then print. but it performs computations using hexadecimal values. So when i input 5 for example: it would be 0x35 + 0x35 = 0x6A then Ox6a would printout as 'j' according to the ASCII tables Im currently using this interrupt for user input. Nettet25. jan. 2016 · Knowing that you want to input a maximum of 3 characters, the correct structure is: inp db 4,0,4 dup (0) It's 4 (not 3) because DOS will also append a carriage … cisco jabber unity connection